Integrated yields

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(partial clean-up)
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p-gamma counts expected using the equation following equation 6.44b in the manual:
p-gamma counts expected using the equation following equation 6.44b in the manual:
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Detected p-gamma coincident events <math>N_i = 10^(-30) [Q / qe] [N_A / A] Y(I_i-->I_f) \epsilon_p \epsilon_\gamma \Delta \Omega_\gamma</math>
+
Detected p-gamma coincident events  
 +
 
 +
<math>N_i = 10^(-30) [Q / qe] [N_A / A] Y(I_i-->I_f) \epsilon_p \epsilon_\gamma \Delta \Omega_\gamma</math>
If the absolute efficiency is known well, then it is possible to retrieve
If the absolute efficiency is known well, then it is possible to retrieve
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equation.
equation.
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In the equation above the <math>epsilon_gamma</math> is the absolute
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In the equation above the <math>\epsilon_\gamma</math> is the absolute
efficiency as a fraction between 0 and 1 (not including angular effects already
efficiency as a fraction between 0 and 1 (not including angular effects already
integrated in the "yield").  Let this be called the absolute photopeak efficiency.
integrated in the "yield").  Let this be called the absolute photopeak efficiency.
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The <math>\Delta\Omega_gamma</math> term is the solid angle of the Ge detector.  A typical absolute photopeak efficiency <math>\epsilon_\gamma<\math> is 10--15%.  If the solid angle subtended by the crystal is  ~0.1 sr, then for one crystal <math>\epsilon_\gamma \Delta\Omega_\gamma ~ 0.01<\math>.
+
The <math>\Delta\Omega_\gamma</math> term is the solid angle of the Ge detector.  A typical absolute photopeak efficiency  
 +
<math>\epsilon_\gamma</math> is 0.1 to 0.15.  If the solid angle subtended by the crystal is  ~0.1 sr, then for one crystal <math>\epsilon_\gamma \Delta\Omega_\gamma ~ 0.01</math>.
If the laboratory setup and the EM matrix are accurately represented in the Gosia input, then the absolute counts can be obtained:
If the laboratory setup and the EM matrix are accurately represented in the Gosia input, then the absolute counts can be obtained:

Revision as of 14:06, 1 June 2011

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